The Range Of The Function F(K) = K2 + 2K + 1 Is {25, 64}. What Is The Function’s Domain?
The Range Of The Function F(K) = K2 + 2K + 1 Is {25, 64}. What Is The Function’s Domain?. What is the function’s domain? I.e., k = 1 or 1 − 2 k − 2 sin 2 x = 0.
I.e., k = 1 or 1 − 2 k − 2 sin 2 x = 0. When k = 5, k² + 2k + 1 = 36. The range of the function f(k) = k2 + 2k + 1 is {25, 64}.
The Range Of The Function F(K) = K2 + 2K + 1 Is {25, 64}.
What is the function s domain? F ′ (x) = (k − 1) (k − 2) (− 2 1 sin 2 x ) + (k − 1) = (k − 1) [1 − 2 k − 2 sin 2 x ] since f(x) does not possess critical points therefore f'(x) is not equal to zero. I.e., k = 1 or 1 − 2 k − 2 sin 2 x = 0.
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K 2 + 2k + 1 = 25. We are given the function {eq}f(k) = k^2 + 2k + 1 {/eq}. The range of the function f (k)=k 2 +2k+1 is {25, 64}.
Asked Feb 27 In Calculus.
When k = 5, k² + 2k + 1 = 36. The domain and range calculator finds all possible x and y values for a given function. The range of the function f(k) = k^2 + 2k + 1 is {25, 64}.
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The range of the function f (k) = k² + 2k + 1 is {25, 64}. Found 2 solutions by mathlover1, ikleyn: Ie k² + 2k + 1 can only take two values 25 or 64.
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